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**A Train has a Speed of 60KM/H for the First One Hour and 40 km/h For the Next Half Hour**

**A.** 40km/h**B.** 48km/h**C.** 53.33km/h**D.** None of these

**Answer –** (C) 53.33km/h

**Explain:-**

**Given:**

**Speed** = 60km/h**First four** = 40km/h

**Solve:**

train has a speed of 60km/h for the first one hour,

` t₁ =1hr, v₁=60km/hr`

Distance covered by the train, d₁ =v₁t₁

` d₁ = 60×1 km`

For the next half hour, train has speed 40km/hr

```
v₂ =40km/hr, t₂ =0.5hr
d₂ = v₂t₂
d₂ =40×0.5=20km
Total distance, d= d₁ + d₂
d=60+20=80km
Total time, t = t₁ + t₂
t=1hr+0.5hr=1.5hr
```

Average speed, v(avg) = d/t

v(avg) = 80km/1.5hr

=53.33km/h

Answer = 53.33km/h

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